Finding the height of a
pendulum
from a pendulum angle

KE_{1} + PE_{1} = KE_{2} +
PE_{2}

Ex) A pendulum is pulled back at an
angle of 10 degrees from the vertical and is released.
When the ball reaches the lowest point, it has a
velocity of 2 m/s.

What is the frequency of the pendulum?

KE_{1} + PE_{1} = KE_{2} +
PE_{2}

mgh = = 1/2mv^{2}

mg(L - Lcosq) = 1/2mv^{2}

L = 13.2 m

T = 7.2 sec

T = 1/f

T = .14 Hz

Giancoli p. 317) 2, 3, 5, 8, 28, 30, 32

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